Answer: A. 85.7
Explanation:
Given : Two sections of a class took the same quiz.
Section A had 15 students who had a mean score of 80, and Section B had 20 students who had a mean score of 90.
We know that ,
![\text{Mean}=\frac{\text{Sum of observations}}{\text{No. of observations}}](https://img.qammunity.org/2020/formulas/mathematics/high-school/op2y98xb7wk8y2i1czabma79rlr4ebuujt.png)
Then , for section A :
![\text{Mean score }=\frac{\text{Sum of scores in sec A}}{\text{No. of students}}](https://img.qammunity.org/2020/formulas/mathematics/high-school/xlzcoak3pf6xw85dag2wih8w1mzlaqdxve.png)
![\Rightarrow\ 80=\frac{\text{Sum of scores in sec A}}{15}\\\\\Rightarrow\ \text{Sum of scores in sec A}=80*15=1200](https://img.qammunity.org/2020/formulas/mathematics/high-school/tgor1v90vopsg1mlao6mb3nva9m0rkrbmm.png)
Similarly in Section B,
![\text{Sum of scores in sec B}=90*20=1800](https://img.qammunity.org/2020/formulas/mathematics/high-school/qxy4bkrcf6f9mxow4hqdxr7889tgoakvks.png)
Total scores = Sum of scores in sec A+Sum of scores in sec B
=1200+1800=3000
Total students = Students in sec A +Students in sec B
=15+20=35
Now , the mean score for all of the students on the quiz =
![\frac{\text{Total score}}{\text{Total students}}](https://img.qammunity.org/2020/formulas/mathematics/high-school/u8qsbdtxtnipwu6qcyjpbxpqehoeb9h9fd.png)
![=(3000)/(35)=85.7142857143\approx85.7](https://img.qammunity.org/2020/formulas/mathematics/high-school/mwzpx6z2mazrsy4kqrcd26yvrqvopyfgth.png)
Hence, the approximate mean score for all of the students on the quiz = 85.7
Thus , the correct answer is option A. 85.7.