Question

One of the deepest freedives (i.e. without any breathing apparatus) to date was achieved by Goran Colak of Serbia when he dove to a depth of 288 m in 2014. If the density of sea water is 1030 kg/m3 and the atmospheric pressure at sea level (1 atm) is 105 Pa, what is the approximate pressure experienced by Goran at that depth

Answer 1

3010038.4 Pa

Step-by-step explanation:

`P_0` = Atmospheric pressure =
`10^5\ Pa`

`\rho` = Density of sea water = 1030 kg/m³

g = Acceleration due to gravity = 9.81 m/s²

h = Depth = 288 m

The total pressure at the given depth is given by

`P=P_0+\rho gh\\\Rightarrow P=10^5+1030* 9.81* 288\\\Rightarrow P=3010038.4\ Pa`

The pressure experienced by Goran at that depth is 3010038.4 Pa