Answer:
10.1 s
Explanation:
Using equation of linear motion
h = ut + 1/2gt² where u = initial velocity = 0, the height from which the object is dropped = 500 m, g, acceleration due to gravity = 9.81m/s² and t is time in seconds
substitute the values into the equation
500 = 0t + 1/2gt²
500 × 2 = 9.81t²
1000 / 9.81 = t²
101.94 = t²
take square root of both side
√101.94 = t
t = 10.1 s