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A solid conducting sphere with radius R that carries positive charge Q is concentric with a very thin insulating shell of radius 2R that also carries charge Q. The charge Q is distributed uniformly over the insulating shell.

User Siddarth G
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1 Answer

3 votes

Answer:

The specific question is not stated, however the general idea is given in the attached picture. The electric field in each region can be found by Gauss’ Law.

at r < R:

Since the solid sphere is conducting, the total charge Q is distributed over the surface, and the electric field inside the sphere is zero.

E = 0.

at R < r < 2R:

The electric field can be found by Gauss’ Law as in the attachment. The green pencil shows this exact region.

at 2R < r:

The electric field can again be found by Gauss’ Law, the blue pencil shows the calculations for this region.

Step-by-step explanation:

Gauss’ Law is straightforward when applied to spheres. The area of the sphere is
A = 4\pi r^2, and the enclosed charge is given in the question as Q for the inner sphere, and 2Q for the whole system.

A solid conducting sphere with radius R that carries positive charge Q is concentric-example-1
User JC Raja
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