Question

to one another, what would the balloon look like at that point compared to initially?HINT: proportionally means, for example, if one doubled in value, so did the other, or if one halved, so did the other, etc.A.Its volume would increase due to the temperature change.B.Its volume would decrease due to both the temperature and pressure changes.C.its volume would remain unchanged--it would look like it did when it first left the groundD.Its volume would decrease due to both the pressure change.E.It's volume would increase due to both the temperature and pressure changes.

Answer 1

C. its volume would remain unchanged--it would look like it did when it first left the ground

Step-by-step explanation:

There is some info missing. I think this is the original question.

If a balloon was placed in a container where the pressure and temperature BOTH decreased proportionally to one another, what would the balloon look like at that point compared to initially?

HINT: proportionally means, for example, if one doubled in value, so did the other, or if one halved, so did the other, etc.

A. Its volume would increase due to the temperature change.

B. Its volume would decrease due to both the temperature and pressure changes.

C. its volume would remain unchanged--it would look like it did when it first left the ground

D. Its volume would decrease due to both the pressure change.

E. Its volume would increase due to both the temperature and pressure changes.

The gas initially occupies a volume V₁ at a temperature T₁ and pressure P₁. Let's suppose that the pressure and temperature are halved (they decrease proportionally to one another). Then,

P₂ = 0.5 P₁

T₂ = 0.5 T₁

We can find the volume V₂ using the combined gas law.

`(P_(1).V_(1))/(T_(1)) =(P_(2).V_(2))/(T_(2)) \\(P_(1).V_(1))/(T_(1)) =(0.5P_(1).V_(2))/(0.5T_(1))\\V_(2)=V_(1)`