Answer:
D) 4.8 × 10² M/s
Step-by-step explanation:
Let's consider the following generic reaction.
A → B
The rate law is:
v = k . [A]ⁿ
where,
v: velocity
k: rate constant
[A]: concentration of the reactant A
n: reaction order for A
What is the velocity of a first-order reaction when the reactant concentration is 6 × 10⁻²M and the rate constant is 8 × 10³s⁻¹?
v = k . [A]¹ = 8 x 10³s⁻¹ . 6 x 10⁻²M = 4.8 × 10² M/s