Answer:
1.29 kg
Step-by-step explanation:
mass of stick (Ms) = 0.113 kg
first mass (Ma) = 0.607 kg
second mass (Mb) = ?
force on the string (Fs) = 19.7 N
acceleration due to gravity (g) = 9.81 m/s^{2}
Find the value of the second mass (Mb).
since the meter stick is in rotational and translational equilibrium, the sum of upward forces is equal to the sum of downward forces irrespective of where the forces act on the meter stick.
therefore
- force on string (Fs) = force of first mass (FA) + force of second mass (FB) + force of meter stick's weight (FW)
- Fs = FA + FB + FW
- force = mg
- Fs = Ma.g + Mb.g + Ms.g
- 19.7 = (0.607 + Mb + 0.113) x 9.81
- 19.7/9.81 = 0.607 + 0.113 + Mb
- 2.01 = 0.720 + Mb
- Mb = 2.01 - 0.720
- Mb = 1.29 Kg
the value of the second mass is 1.29 kg