Question

A boy kicks a football from ground level. The ball takes 3 seconds to reach its maximum height. What is the angle of the initial velocity with respect to the horizontal, if the ball lands 15 m away from the launching point?

Answer 1

The angle of the initial velocity with respect to the horizontal is 85.14°

Step-by-step explanation:

Given that the ball takes 3 seconds to reach its maximum height.

Consider the vertical motion of ball till maximum height.

We have equation of motion v = u + at

Acceleration, a = -9.81 m/s²

Final velocity, v = 0 m/s

Time, t = 3 s

Substituting

v = u + at

0 = u + -9.81 x 3

u = 29.43 m/s

Initial vertical velocity is 29.43 m/s.

Now consider horizontal motion of ball.

Time of flight of ball = 2 x Time to reach maximum height = 2 x 3 = 6 s

Displacement = 15 m

We have equation of motion s = ut + 0.5 at²

Displacement, s = 15 m

Acceleration, a = 0 m/s²

Time, t = 6 s

Substituting

s = ut + 0.5 at²

15 = u x 6 + 0.5 x 0 x 6²

u = 2.5 m/s

Initial horizontal velocity is 2.5 m/s

Let r be the initial velocity and θ be the angle with horizontal

Initial vertical velocity = rsinθ = 29.43 m/s

Initial horizontal velocity = rcosθ = 2.5 m/s

Dividing

`(rsin\theta )/(rcos\theta )=(29.43)/(2.5)\\\\tan\theta=11.77\\\\\theta=85.14^0`

The angle of the initial velocity with respect to the horizontal is 85.14°