Answer:
four less than the quotient of a number cubed and seven, increased by three
![((n^3)/(7) -4)+3](https://img.qammunity.org/2020/formulas/mathematics/middle-school/azxtr2n6zszs7fw1fc9vaplvk9dv59jgsn.png)
five times the difference of a number squared and six
![5(n^2 -6)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/d1h4jvoju0hnf7kqv9qrz6344ilgoqbw4p.png)
nine more than the quotient of six and a number cubed, decreased by four
![9+(6)/(n^3)-4](https://img.qammunity.org/2020/formulas/mathematics/middle-school/ve05283ytk29d4v3ev9ypaf8rzqqyl01i3.png)
twice the difference of nine and a number squared
![2(9-n^2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/3z5kijfozqb47jitu7m6rcdnuj1l5huw8l.png)
Explanation:
Let n the number of interest we have this:
four less than the quotient of a number cubed and seven, increased by three
![((n^3)/(7) -4)+3](https://img.qammunity.org/2020/formulas/mathematics/middle-school/azxtr2n6zszs7fw1fc9vaplvk9dv59jgsn.png)
five times the difference of a number squared and six
![5(n^2 -6)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/d1h4jvoju0hnf7kqv9qrz6344ilgoqbw4p.png)
nine more than the quotient of six and a number cubed, decreased by four
![9+(6)/(n^3)-4](https://img.qammunity.org/2020/formulas/mathematics/middle-school/ve05283ytk29d4v3ev9ypaf8rzqqyl01i3.png)
twice the difference of nine and a number squared:
![2(9-n^2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/3z5kijfozqb47jitu7m6rcdnuj1l5huw8l.png)