Question

In the figure to the right, AE + DC = 1 1/5 cm, AB = 1 3/4 cm, DE = 1 1/4 cm, and BC = 1 3/10 cm. Find the perimeter of the figure.

Answer 1

5 1/2

Explanation:

just 5 1/2 :)

Answer 2

`5(1)/(2)\ cm`

Explanation:

The perimeter of the shown figure is the sum of the lengths of all sides. So, the perimeter is

`AE+ED+DC+CB+AB`

Using commutative and reflexive properties, rewrite it as follows:

`(AE+DC)+DE+BC+AB`

Therefore, the perimeter is

`P\\ \\=1(1)/(5)+1 (1)/(4)+1(3)/(10)+1(3)/(4)\\ \\=(1+1+1+1)+\left((1)/(5)+(3)/(10)\right)+\left((1)/(4)+(3)/(4)\right)\\ \\=4+\left((2)/(10)+(3)/(10)\right)+1\\ \\=5+(5)/(10)\\ \\=5+(1)/(2)\\ \\=5(1)/(2)\ cm`