Answer:
V=1.19m/s
Step-by-step explanation:
A 30-06 caliber hunting rifle fires a bullet of mass 0.018 kg with a velocity of 417 m/s to the right. The rifle has a mass of 6.29 kg. What is the recoil speed of the rifle as the bullet leaves the rifle?
this momentum.
it has to deal with the interaction between bullet and a gun
.lets have a deep dive into the solution
momentum is the product of mass of a body and the velocity
momentum of the bullet-=momentum of the gun
mv=MV
mass of bullet=0.018kg
v=velocity of bullet
M=mass of rifle 6.29kg
V=recoil velocity of the rifle gun
0.018*417=6.29*V
V=1.19m/s
mass is the quantity of matter in a body
velocity is change in displacement per time