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A magnetic B field of strength 18 T is perpendicular to a conducting loop of wire measuring 0.9 square meters with 30 turns. If the B field is linearly reduced to zero in 4 s, then what is the magnitude of the induced emf voltage? (in units of V).

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Answer:

magnitude of the induced emf voltage = 121.5 V

Step-by-step explanation:

given data

magnetic field of strength B = 18 T

area = 0.9 m²

no of turn = 30 turns

Δt = 4s

to find out

magnitude of the induced emf voltage

solution

we get her magnitude of the induced emf voltage that is express as

magnitude of the induced emf voltage =
(d\phi)/(dt) ......1

magnitude of the induced emf voltage =
n*a * (dB)/(dt)

magnitude of the induced emf voltage =
30* 30* (18)/(4)

magnitude of the induced emf voltage = 121.5 V

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