What is the distance between (-2 1/2,-3) and (1,-3

Question

asked Sep 19, 2020 44.5k views

2 Answers

Stan Fad · Answer 1 · 2020-09-23T08:48:49+0000

Answer:

$3(1)/(2)\ units$

Explanation:

we know that

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^(2)+(x2-x1)^(2)}$

we have

$(-2(1)/(2),-3)\ and\ (1,-3)$

Convert mixed number to an improper fraction

2(1)/(2)=(2*2+1)/(2)=(5)/(2)

so

we have

$(-(5)/(2),-3)\ and\ (1,-3)$

substitute the values in the formula

$d=\sqrt{(-3+3)^(2)+(1+(5)/(2))^(2)}$

$d=\sqrt{(0)^(2)+((7)/(2))^(2)}$

$d=(7)/(2)\ units$

Convert to mixed number

$(7)/(2)\ units=(6)/(2)+(1)/(2)=3(1)/(2)\ units$