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Say that there were a planet X in our Solar System with a mass 1/4 the mass of Earth and a radius 1/2 the radius of Earth. How will the gravity on its surface compare to the surface gravity of Earth?

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Answer:

The gravity on the surface of the planet X will be equal to the gravity on the surface of the Earth.

Step-by-step explanation:

The gravity (g) on the surface of a planet can be calculated using an expression derived from Newton's law of universal gravitation.


g=(G.M)/(r^(2) )

where,

G: gravitational constant

M: mass of the planet

r: radius of the planet

The gravity on the surface of the Earth is:


gE=(G.M_(E))/(r_(E)^(2) )

For the planet X,

mX = 1/4 mE

rX = 1/2 mE

The gravity on the surface of the planet X is:


gX=(G.M_(X))/(r_(X)^(2) )=(G.1/4M_(E))/((1/2r_(E))^(2) ) =(G.M_(E))/(r_(E)^(2) )=gE

The gravity on the surface of the planet X will be equal to the gravity on the surface of the Earth.

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