Question

There is a rectangular section of his yard. the perimeter of the section is 27 feet and the are is 35 square feet find the length and width of the section. p=2(L+W) if the perimeter is 27 feet solve for W. The equation for area is A=LW, substitute the expression you found for W in part 1 into the area equation. Then, if the area is equal to 35 square feet write the equation in standard form with a,b, and c as whole numbers.

Answer 1

2L^2 - 27L + 70 = 0.

Explanation:

p = 2(L + W)

27 = 2L + 2W

2W = 27 - 2L

W = (27 - 2L)/2

Substitute for W in the area equation:

A = LW

35 = (27 - 2L) * L / 2

L(27 - 2L) = 70

-2L^2 + 27L - 70 = 0 Multiply through by -1:

2L^2 - 27L + 70 = 0