Question

A large container contains a large amount of water. A hole is drilled on the wall of the container, at a vertical distance h = 0.54 m below the surface of the water. The water surface drops very slowly and its speed is approximately zero. Keep 2 decimal places in all answers. (

Find the speed v (in m/s) at which water squirts out of the hole.

Answer 1

Velocity = 3.25[m/s]

Step-by-step explanation:

This problem can be solved if we use the Bernoulli equation: In the attached image we can see the conditions of the water inside the container.

In point 1, (surface of the water) we have the atmospheric pressure and at point 2 the water is coming out also at atmospheric pressure, therefore this members in the Bernoulli equation could be cancelled.

The velocity in the point 1 is zero because we have this conditional statement "The water surface drops very slowly and its speed is approximately zero"

h2 is located at point 2 and it will be zero.

`(P_(1) +(v_(1)^(2) )/(2g) +h_(1) )=(P_(2) +(v_(2)^(2) )/(2g) +h_(2) )\\P_(1) =P_(2) \\v_(1)=0\\h_(2) =0\\v_(2)=√(0.54*9.81*2)\\v_(2)=3.25[m/s]`