Question

If 35.4067=3/p+5/q+4r+6/s+7t, then the value of 2p+4q+5r+7s+3t​

Answer 1

7004.7003

Explanation:

We are given the following information in the question:

`35.4067=\displaystyle(3)/(p)+(5)/(q)+4r+(6)/(s)+7t`

We know that,

`35.4067 = (3* 10^1) + (5* 10^0) + (4* 10^(-1))+(0* 10^(-2)) + (6* 10^(-3)) + (7* 10^(-4))`

Comparing the two equations, we get:

`\displaystyle(1)/(p) = 10^1\\\\p = 10^(-1)\\q = 10^0\\r = 10^(-1)\\s = 10^3\\t = 10^(-4)`

We have to evaluate:

`2p+4q+5r+7s+3t`

Putting values, we get:

`(2* 10^(-1)) + (4* 10^0) + (5* 10^(-1)) + (7* 10^3) + (3* 10^(-4))\\=0.2 + 4 + 0.5 + 7000 + 0.0003\\=7004.7003`