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The point A (5,11) is reflected across the x-axis. How long is the segment AA'?


User Crifan
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2 Answers

3 votes

Final answer:

The reflected point of A (5,11) across the x-axis is A' (5,-11). Using the distance formula derived from the Pythagorean theorem, the length of segment AA' is calculated to be 22 units.

Step-by-step explanation:

When reflecting a point across the x-axis, the x-coordinate remains the same, but the y-coordinate changes sign. For the point A (5,11), its reflected point A' would be (5,-11). To find the length of the segment AA', we can use the distance formula, which is derived from the Pythagorean theorem.

The distance formula is √((x2 - x1)² + (y2 - y1)²), where (x1, y1) and (x2, y2) are the coordinates of the two points. Applying this to our points A and A', the distance is √((5 - 5)² + (-11 - 11)²) = √(0 + (-22)²) = √484 = 22 units.

Therefore, the length of segment AA' is 22 units.

User Ridcully
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8.7k points
1 vote

Answer: The required length of the segment AA' is 11 units.

Step-by-step explanation: Given that the point A(5, 11) is reflected across the X-axis.

We are to find the length of the segment AA'.

We know that

if a point (x, y) is reflected across X-axis, then its co-ordinates becomes (x, -y).

So, after reflection, the co-ordinates of the point A(5, 11) becomes A'(5, -11).

Now, we have the following distance formula :

The DISTANCE between two points P(a, b) and Q(c, d) gives the length of the segment PQ as follows :


PQ=√((c-a)^2+(d-b)^2).

Therefore, the length of the segment AA' is given by


AA'=√((5-5)^2+(-11-11)^2)=√(11^2)=11.

Thus, the required length of the segment AA' is 11 units.

User Kyle Kastner
by
8.2k points

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