Answer:
50 h
Step-by-step explanation:
The heat required (Q) to heat the water can be calculated using the following expression.
Q = c × m × ΔT = (4.184 kJ/kg.°C) × 1000 kg × (200°C - 60°C) = 5.9 × 10⁵ kJ
where,
c: specific heat capacity
m: mass
ΔT: change in the temperature
The solar collector has an area of 6 m² and the intensity delvered by sunlight is 550 W/m². The power (P) submitted by the collector is:
6 m² × 550 W/m² = 3 × 10³ W
The energy collected is transformed into heat. We know that:
P = E/t = Q/t
where
t: time
t = Q/P = 5.9 × 10⁸ J / (3 × 10³ J/s) = 2 × 10⁵ s × (1 h / 3600 s) = 50 h