Answer:
1) mass in grams = 34 g or generally 2 multiply molar mass of product
2) mass in of one mole = 17 g or generally 1 multiply molar mass of product
3) Option C = AB₃
Step-by-step explanation:
Data given:
2 diatomic molecules react and form product
it basically
- 3 AA + BB ---> 2 products
- 3 volumes + 1 volume ---> 2 volumes product
- 3 liters + 1 liter ---> 2 liters product
- 3 moles (A2) + 1 mole B2 ---> 2 moles product
grams of product =?
mass of one mole of product =?
correct formula for the product reaction = ?
Solution:
First we have to identify the two diatomic molecule that combine in 3 to 1 ratio.
So it can be the following:
3H₂ + N₂ -------> 2NH₃
So it have 3 to 1 ratio in all respect
3H₂ + N₂ -------> 2NH₃
- 3 volumes of hydrogen molecule + 1 volume of nitrogen atom ---> 2 volumes ammonia
- 3 liters + 1 liter ---> 2 liters product
- 3 moles (A2) + 1 mole B2 ---> 2 moles product
Now to find the grams of products
3H₂ + N₂ -------> 2NH₃
3 mol 1 mol 2 mol
so 2 moles of product are formed
To find find mass in gram formula will be used
mass in grams = no. of moles x molar mass
molar mass of NH₃ = 14 + 3(1) = 17 g/mol
put value in formula
mass in grams = 2 mol x 17 g/mol
mass in grams = 34 g
So,
the mass of the product will be 34 grams
or generally 2 multiply by molar mass of the product.
2) mass of 1 mole of product:
look at the reaction:
3H₂ + N₂ -------> 2NH₃
use the formula
mass in grams = no. of moles x molar mass. . . . .(1)
molar mass of NH₃ = 14 + 3(1) = 17 g/mol
so for 1 mole
no. of moles = 1
put values in formula 1
mass in grams = 1 mol x 17 g/mol
mass in grams = 17 g
So,
the mass of 1 mol product is 17 grams
or generally 1 multiply by molar mass of the product.
3) Correct Formula
Again look at the related reaction
3H₂ + N₂ -------> 2NH₃
As two molecules are diatomic but one have 1 valency and other have 3 valency.
So it is clear from the reaction that is the product formula is NH₃.
So, option c is correct
Option C = AB₃