Question

7)

Hookes Law for an elastic spring states that the distance a spring stretches varies directly as the
be applied. If a force of 15 pounds stretches a certain spring 7 inches, then how much will a force
of 60 pounds stretch the spring?
D) 3 in.
A) 2 in.
C) 28 in
B) 105 in​

Answer 1

C) 28 in.

Explanation:

Given:

Hooke's Law for an elastic spring states that "the distance a spring stretches varies directly as the force to be applied."

Hence we can say that;

F ∝ D

F = k . D

where,

F ⇒ Force applied

D⇒ Distance of spring

k⇒ constant

Now Given:

Force (F) = 15 pounds

Distance of Spring (D) = 7 inches

Substituting the values in above equation we get;

`15=k* 7\\\\k = (15)/(7) \approx 2.143\ pounds/inches`

Now we need to find Distance of the spring stretched when Force is 60 pounds.

`F =kD\\\\D = (F)/(k)`

Substituting the values we get;

`D = (60)/(2.143) \approx 28\ inches`

Hence the distance of spring stretched will be 28 inches when a force of 60 pounds applied to it.