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A ball of mass m strikes a wall perpendicularly with a speed v, and it bounces off the wall perpendicularly with a speed v 5 . What is the magnitude of the impulse delivered to the wall by the ball?

User Baltekg
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1 Answer

2 votes

Answer:

Step-by-step explanation:

Given

mass of ball is m

initial velocity of ball is
v

Final velocity of ball is
v_5

Impulse is the change in momentum of an object when an external force is applied for a given interval of time.

Initial momentum
P_i=mv

Final momentum
P_f=mv_5


Impulse=P_f-P-i=m(v_5-v)

User Thomas Cayne
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