Question

A ball is revolving horizontally in a circle of radius 1.8 m, and is held by a rigid, massless rod. The mass of the ball is 0.1 kg. The path of the ball has a constant linear speed of 27 m/s. What is the angular velocity of the orbit in rad/s?

Answer 1

`\omega=15 \ rad/s`

Step-by-step explanation:

given,

radius of circle = 1.8 m

mass of the ball = 0.1 Kg

linear speed of the ball = 27 m/s

angular velocity of orbit = ?

`v =  r \omega`

ω is the angular speed of the circle

`\omega=(v)/(r)`

`\omega=(27)/(1.8)`

`\omega=15 \ rad/s`

the angular velocity of the orbit is
`\omega=15 \ rad/s`