Question

A block is pulled along a horizontal surface at a constant speed by a force (14.1i 0 j 5.1k). The direction k is perpendicular to the surface. The block moves 6 m. How much work, in N m, does the force do?

Answer 1

`W =84.6\ Nm`

Step-by-step explanation:

given,

F = 14.1 i + 0 j + 5.1 k

displacement = 6 m

Assuming block is moving in x- direction

we know,

dW = F dx

`\int dW = F\int dx`

`W = F\int_0^6 dx`

`W = F[x]_0^6`

`W = 14.1 * 6`

`W =84.6\ Nm`

hence, work done by the force is equal to
`W =84.6\ Nm`