Question

A driver in a 1000 kg car traveling at 32 m/s slams on the brakes and skids to a stop. If the coefficient of friction between the tires and the horizontal road is 0.80, how long will the skid marks be?A. 81 mB. 60 mC. 65 mD. 52 m

Answer 1

Distance traveled will be 65.3 m

So option (c) will be correct option

Step-by-step explanation:

We have given mass of the car m = 1000 kg

Velocity v = 32 m /sec

Coefficient of friction = 0.8

The force on the car will be equal to frictional force

So
`ma=\mu mg`

`a=\mu g=0.8* 9.8=7.84m/sec^2`

When the car stops its final velocity will be zero

According to third equation of motion we know that

`v^2=u^2+2as`

So
`s=(u^2)/(2a)=(32^2)/(2* 7.84)=65.30m`

So option (c) will be correct answer