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What impulse was delivered to the sled by the friction force from the rough spot?

User Nitneuq
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1 Answer

3 votes

Answer:

- 80 Ns

Step-by-step explanation:

The complete statement is given as

A sled and rider, gliding over horizontal, friction less ice at 4.0 m/s, have a combined mass of 80 kg. The sled then slides over a rough spot in the ice, slowing down to 3.0 m/s. What impulse was delivered to the sled by the friction force from the rough spot?


v_(i) = initial velocity of the sled = 4.0 m/s


v_(f) = final velocity of the sled = 3.0 m/s


m = combined mass of sled and rider = 80 kg


I = Impulse delivered to sled

Using Impulse-change in momentum equation, Impulse delivered to sled is given as


I = m (v_(f) - v_(i))\\I = (80) (3 - 4)\\I = - 80 Ns

User FranXho
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