Answer:
The vertical force acting on the firefighter = 908.27 N
Step-by-step explanation:
Force: Force of a body is defined as the product of mass and its acceleration. The S.I unit of force is Newton (N)
The vertical force acting on the firefighter = Force due to the weight of the firefighter + force due to acceleration.
Ft = Fw - Fa
Where Ft = The vertical force acting on the firefighter, Fw = Force due to the weight of the firefighter, Fa = force due to acceleration.
Fw = mg
Making m the subject of formula in the equation above
m = Fw/g................... Equation 1
Where m = mass of the firefighter, g = acceleration due to gravity,
Given: Fw = 707 N,
Constant: g = 9.8 m/s²
Substituting these values into eqaution 1
m = 707/9.8
m = 72.14 kg.
But, Fa = ma
Where a = acceleration of the firefighter.
Given: a = 2.79 m/s²,
And m = 72.14 kg
Fa = 72.14 × 2.79
Fa = 201.27 N
Therefore, Ft = 707 + 201.27 = 908.27 N
Ft = 908.27 N
The vertical force acting on the firefighter = 908.27 N