Question

A ball is kicked from ground level with a velocity of 20 m/s at 30 degrees above the horizontal. Determine the horizontal displacement to where it lands and find how high the ball went at max height.

Answer 1

Answer:the horizontal displacement is 34.64 meters

The maximum height is 15 meters

Explanation:

As the ball moves from the ground at 30 degrees, it travels through a parabolic path. It can therefore be likened to a projectile. The horizontal displacement to where it lands is the range. The formula for determining range,R is

R = U^2Sin2#)/g

Where

U represents the initial velocity of the ball

g is acceleration due to gravity

# represents the angle above the horizontal.

From the information given

# = 30 degrees

U = 20 m/s

g = 10m/s^2

R = 20^2Sin2×30)/10 = (400Sin60)/20 = (400×0.8660)/10

= 34.64 meters

To determine the maximum height of the ball, H,

H = (U^2Sin^2#)/2g

H = (20^2 × Sin^2 30)/2×10

H = (400 × 0.866^2)/20 = 15 meters