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A square-based shipping crate is being designed that must contain a volume of 16 ft3 . The material that is used for the base and the lid costs 3 dollars/ft2 , while the material used for the sides costs 2 dollars/ft2 . What are the most cost-effective dimensions of such a crate?

User Jwynveen
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1 Answer

2 votes

Answer:

Step-by-step explanation:

Given

volume
V=16 ft^3

Suppose base is square with side L

height of crate is h

Volume
V=L^2* h


16=L^2* h

Cost of top and bottom area
c_1=3L^2

Cost of Side area
c_2=4Lh* 2=8Lh=8L* (16)/(L^2)=(128)/(L)

Total Cost
C=c_1+c_2

Total Cost
C=3L^2+(128)/(L)

Differentiate C w.r.t Length


(dC)/(dL)=6L-(128)/(L^2)


L^3=(128)/(6)


L=2.75 ft


h=(16)/(2.75^2)=11.46 ft

Dimensions are
L* L* h=2.75* 2.75* 11.46

User Puppymaster
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