Question

Suppose you and a friend, each of mass 60 kg, go to the park and get on a 4.0-m-diameter merry-go-round. You stand on the outside edge of the merry-go-round, while your friend pushes so that it rotates once every 6.0 s. What is the magnitude of the (apparent) outward force that you feel?

A. 7 N
B. 63 N
C. 130 N
D. 260 N

Answer 1

The magnitude of centripetal force is 130 N.

Step-by-step explanation:

It is given that,

Mass, m = 60 kg

Diameter of the merry go round, d = 4 m

Radius, r = 2 m

Time for rotation, t = 6 s

We know that we will feel some of the outward force and this force is known as centripetal force. Its formula is given by :

`F=(mv^2)/(r)`

v is the velocity

`v=(2\pi r)/(t)`

`v=(2\pi * 2)/(6)`

v = 2.09 m/s

`F=(60* (2.09)^2)/(2)`

F = 131.04 N

or

F = 130 N

So, the magnitude of centripetal force is 130 N. Hence, this is the required solution.