Answer:
![1.7\cdot 10^(15) g](https://img.qammunity.org/2020/formulas/chemistry/college/2hxxlvkzszqbbvvyg17ooeie9vq6vgnlgy.png)
Step-by-step explanation:
Glucose reacts with oxygen do produce carbon dioxide and water:
![C_6H_12O_6 (s) + 6 O_2 (g)\rightarrow 6 CO_2 (g) + 6 H_2O (l)](https://img.qammunity.org/2020/formulas/chemistry/college/7vbuodqupgqt3avmqb9dhaf8xd67b79ltg.png)
Given a daily mass of glucose:
![m_1 = 5.0\cdot 10^2 g](https://img.qammunity.org/2020/formulas/chemistry/college/ktf9pgy2wx7tvliuykvaed3s9fhk8knkng.png)
Find moles of glucose:
![n_1 = {5.0\cdot 10^2 g}{180.156 g/mol} = 2.775 mol](https://img.qammunity.org/2020/formulas/chemistry/college/n8zs8sa213qhcpwtukqjge711ijcxqybbe.png)
From stoichiometry of this equation, moles of carbon dioxide can be found by multiplying this amount by 6:
![n_2 = 2.775 mol\cdot 6=16.65 mol](https://img.qammunity.org/2020/formulas/chemistry/college/vjxl5fzd65dzdzlmvj0fs8bjyo8462fbk8.png)
Convert this into mass using the molar mass of carbon dioxide:
![m_2 = 16.65 mol\cdot 44.01 g/mol = 732.8 g](https://img.qammunity.org/2020/formulas/chemistry/college/fgax2z0o2fwygcbzg7jvg4jldg4a3r03xh.png)
This is the mass of carbon dioxide per person per day. Multiply by the population and by the number of days to get the total mass:
![732.8 (g)/(person\cdot day)\cdot 365 days\cdot 6.5\cdot 10^9 people = 1.7\cdot 10^(15) g](https://img.qammunity.org/2020/formulas/chemistry/college/cvr4nj7d7ot4g0v4ncyiwbn0upez34czm5.png)