Question

An ac generator consists of a coil with 40 turns of wire, each with an area of 0.06 m2. The coil rotates in a uniform magnetic field B = 0.4 T at a constant frequency of 55Hz. What is the maximum induced emf?

Answer 1

331.75 V

Step-by-step explanation:

Given:

Number of turns of the coil, N = 40 turns

Area, A = 0.06 m²

Magnetic Field, B = 0.4 T

Frequency, f = 55 Hz

Maximum induce emf, E₀ = NABω

but ω = 2πf

Maximum induce emf, E₀ = NAB(2πf₀)

Maximum induce emf, E₀ = 2πNABf₀

Where;

N is number of turns of the coil

A is area

B is magnetic field

ω is the angular velocity

f is the frequency

E₀ = 2 × π × 40 × 0.06 × 0.4 × 55

E₀ = 342.81 V

The maximum induced emf is 331.75 V