Answer:
1 hour
Step-by-step explanation:
speed of Thato (St) = 2.5 mi/h
speed of Edwin (Se) = 3.5 mi/h
distance (d) = 6 mi
How many hours pass before they meet on the trail?
- lets assume that they both meet when the time = T hours
- At time = T hours, the distance covered by Thato = speed x time
= 2.5 x T = 2.5T
- At time = T hours, the distance covered by Edwin = speed x time
= 3.5 x T = 3.5T
- At the time they meet (T hours) the addition of the distance covered by both Thato and Edwin would be 6 mi (the total distance covered by both of them would be 6 mi)
- 2.5T + 3.5T = 6
6T = 6
T = 1 hour