Question

10. At point A, a runner is jogging 5 m/s. Forty seconds later, at point B

(Up hill) the jogger's velocity is only 2 m/s. What is the jogger's
acceleration from point A to point B?

Answer 1

Deceleration of 0.075m/s²

Step-by-step explanation:

Given parameters:

Initial velocity = 5m/s

Time = 40s

Final velocity = 2m/s

Unknown:

The jogger's acceleration = ?

Solution:

To solve this problem, we use;

a =
`(v - u)/(t)`

a is the acceleration

v is the final velocity

u is the initial velocity

t is the time taken

a =
`(2 - 5)/(40)` = - 0.075m/s²