Question

What is the electric potential energy of a charge that experiences a force of 3.6 × 10–4 N when it is 9.8 × 10–5 m from the source of the electric field? 3.5 × 10–8 J 4.6 × 10–4 J 2.7 × 10–1 J 3.7 × 100 J

Answer 1

Answer: A. 3.5 × 10–8 J

Explanation: edge 2021

Answer 2

`3.5*10^(-8) J`

Step-by-step explanation:

`F` = Force experienced by the charge =
`3.6*10^(-4) N`

`q_(1)` = magnitude of charge producing the electric field

`q_(2)` = magnitude of charge experiencing the electric force

`r_(1)` = distance between the two charges

Electric force experienced by the charge is given using coulomb's law as

`F = (k q_(1) q_(2))/(r^(2) ) \\3.6*10^(-4) =((9*10^(9)) q_(1) q_(2))/((9.8*10^(-5))^(2) ) \\q_(1) q_(2) = 3.8416*10^(-22)`

Electric potential energy of the charge can be given as

`U = (k q_(1) q_(2))/(r ) \\U = ((9*10^(9)) q_(1) q_(2))/((9.8*10^(-5))) \\U = 3.5*10^(-8) J`