Question

If an individual who is heterozygous for both genes (AaBb) mates with an individual that is homozygous recessive for both gene's (aabb). How many of their offspring would show a recombinant phenotype?

Answer 1

Eight among 16 offspring are recombinant phenotype i.e

Four Aabb and four aaBb offsprings are genotypically and phenotypically different from their parents.

Step-by-step explanation:

Phenotypically Heterozygous dominant X Homozygous recessive

Cross between AaBb X aabb

Gametes produces AB, Ab, aB, ab X ab, ab, ab, ab

Cross between

AB Ab aB ab

ab AaBb Aabb aaBb aabb

ab AaBb Aabb aaBb aabb

ab AaBb Aabb aaBb aabb

ab AaBb Aabb aaBb aabb

Genotypically

four AaBb are produced

four Aabb are produced

four aaBb are produced

four aabb are produced

AaBb and aabb are genotypically and phenotypically same like their parents

Aabb and aaBb are genotypically and phenotypically different from their parents.

So answer is eight among 16 offspring are recombinant phenotype.