Question

Using the quadratic formula to solve 11x2 – 4x = 1, what are the values of x? StartFraction 2 Over 11 EndFraction plus-or-minus StartFraction StartRoot 15 EndRoot Over 11 EndFraction StartFraction 2 Over 11 EndFraction plus-or-minus StartFraction 2 StartRoot 15 EndRoot Over 11 EndFraction StartFraction 2 Over 11 EndFraction plus-or-minus StartFraction StartRoot 7 EndRoot Over 11 EndFraction StartFraction 2 Over 11 EndFraction plus-or-minus StartFraction StartRoot 7 EndRoot i Over 11 EndFraction

Answer 1

a on edg

Explanation:

took the test

Answer 2

`x=(2)/(11)\pm\frac{√(15)} {11}`

Explanation:

we know that

The formula to solve a quadratic equation of the form

`ax^(2) +bx+c=0`

is equal to

`x=\frac{-b\pm\sqrt{b^(2)-4ac}} {2a}`

in this problem we have

`11x^(2) -4x=1`

equate to zero

`11x^(2) -4x-1=0`

so

`a=11\\b=-4\\c=-1`

substitute in the formula

`x=\frac{-(-4)\pm\sqrt{-4^(2)-4(11)(-1)}} {2(11)}`

`x=\frac{4\pm√(60)} {22}`

`x=\frac{4\pm2√(15)} {22}`

`x=\frac{2\pm√(15)} {11}`

`x=(2)/(11)\pm\frac{√(15)} {11}`

therefore

StartFraction 2 Over 11 EndFraction plus-or-minus StartFraction StartRoot 15 EndRoot Over 11 EndFraction