Using the quadratic formula to solve 11x2 – 4x = 1, what are the values of x? StartFraction 2 Over 11 EndFraction plus-or-minus StartFraction StartRoot 15 EndRoot Over 11 EndFra…

Question

asked Aug 9, 2020 227k views

2 Answers

Kapil Choubisa · Answer 1 · 2020-08-13T06:31:13+0000

Answer:

$x=(2)/(11)\pm\frac{√(15)} {11}$

Explanation:

we know that

The formula to solve a quadratic equation of the form

ax^(2) +bx+c=0

is equal to

$x=\frac{-b\pm\sqrt{b^(2)-4ac}} {2a}$

in this problem we have

11x^(2) -4x=1

equate to zero

11x^(2) -4x-1=0

so

$a=11\\b=-4\\c=-1$

substitute in the formula

$x=\frac{-(-4)\pm\sqrt{-4^(2)-4(11)(-1)}} {2(11)}$

$x=\frac{4\pm√(60)} {22}$

$x=\frac{4\pm2√(15)} {22}$

$x=\frac{2\pm√(15)} {11}$

$x=(2)/(11)\pm\frac{√(15)} {11}$

therefore

StartFraction 2 Over 11 EndFraction plus-or-minus StartFraction StartRoot 15 EndRoot Over 11 EndFraction