Answer:
![A_T = \left[\begin{array}{cc}-cos(2/3 \pi)&sen(2/3 \pi)\\sen(2/3\pi)&cos(2/3\pi)\end{array}\right]](https://img.qammunity.org/2020/formulas/mathematics/high-school/xp7lyd77ol8odnssylhxerryc0ned9j2da.png)
Explanation:
60 degree is equivalent to 2/3 π. The linear transformation of a counterclockwise rotation of angle 2/3 π is
![R(2/3 \, \Pi) = \left[\begin{array}{cc}cos(2/3 \pi)&-sen(2/3 \pi)\\sen(2/3\pi)&cos(2/3\pi)\end{array}\right]](https://img.qammunity.org/2020/formulas/mathematics/high-school/3ip868cvj9p5gqqvjj5tc60jx81n37chly.png)
On the other hand, the reflection throught the Y-axis is given by the linear transformation

Hence its associated matrix is
![A_(RY) = \left[\begin{array}{cc}-1&0\\0&1\end{array}\right]](https://img.qammunity.org/2020/formulas/mathematics/high-school/5930x6ohkkx0lraz1qrd5tilu3zj46dhnf.png)
And the composition is given by
![A_T = A_(RY) * R(2/3 \, \Pi) = \left[\begin{array}{cc}-cos(2/3 \pi)&sen(2/3 \pi)\\sen(2/3\pi)&cos(2/3\pi)\end{array}\right]](https://img.qammunity.org/2020/formulas/mathematics/high-school/x4gleoc57jt9r74x15q24ngiwh3lp3idcs.png)