Question

A 110 kg crate is pulled along a level surface by an engine. The coefficient of kinetic friction between the crate and the surface is 0.585. How much power must the engine deliver to move the crate at a constant speed of 7.59 m/s? The acceleration due to gravity is 9.8 m/s 2 . Answer in units of W.

Answer 1

Net power will be 1150.637 watt

Step-by-step explanation:

We have given mass of the crate m = 110 kg

Coefficient of friction
`\mu =0.585`

Acceleration due to gravity
`g=9.8m/sec^2`

Constant speed
`v=7.59m/sec`

Force applied
`F=ma=110* 7.59=834.9N`

Frictional force
`f=\mu mg=0.585* 110* 9.8=630.63N`

So net force
`=834.9-630.6=204.3N`

Power is given by
`P=Fv=204.3* 7.59=1550.637Watt`

So net power will be 1550.637 watt