Answer:
The distance from the Sun to Neptune is 29,41 AU.
Step-by-step explanation:
We know, from the sentence, that the orbit of Neptune has an average diameter around 8.80*10⁹km.
Now, we can calculate the radius of this orbit, which is equivalent to the distance from thsi planet to the Sun. Let's recall tha the radius is the half of the diameter.
![R=(8.80\cdot 10^(9))/(2)=4.4\cdot 10^(9)km=4.4\cdot 10^(12)m](https://img.qammunity.org/2020/formulas/physics/college/l2jj34e1yi3jwk5hj6h2e55j4efu19lpo7.png)
Ok, we know that 1.496*10¹¹m is an AU, therefore we have:
![4.4\cdot 10^(12)m\cdot (1 AU)/(1.496\cdot 10^(11))=29,41 AU](https://img.qammunity.org/2020/formulas/physics/college/uun99vk4xwl7fnjko0b2ijqlw6b6b12lyq.png)
Finally, the distance R is 29,41 AU.
I hope it helps you! :)