Question

A Ferris wheel, rotating initially at an angular speed of 0.500 rad/s, accelerates over a 7.00-s interval at a rate of 0.040 0 rad/s2 . What angular displacement does the Ferris wheel undergo in this 7-s interval? a. 4.48 rad b. 2.50 rad c. 3.00 rad d. 0.500 rad

Answer 1

Angular displacement will be 4.48 rad

So option (a) will be correct option

Step-by-step explanation:

We have given initial angular acceleration
`\omega _i=0.5rad/sec`

Angular acceleration
`\alpha =0.04rad/sec^2`

Time t = 7 sec

We have to find the angular displacement

We know that angular displacement is given by

`\Theta =\omega _it+(1)/(2)\alpha t^2=0.5* 7+(1)/(2)* 0.04* 7^2=4.48rad`

So option (a) will be correct option