Question

Three resistors, 21 Ω, 58 Ω, and 64 Ω, are connected in series, and a 0.50-A current passes through them. What are (a) the equivalent resistance and (b) the potential difference across this equivalent resistance?

Answer 1

a) Equivalent resistance is 143 Ω

b) Potential difference is 71.5 V

Step-by-step explanation:

When resistors are connected in series, effective resistance is given by

`R_(eff)=R_1+R_2+R_3+......`

Here

R₁ = 21Ω

R₂ = 58Ω

R₃ = 64Ω

a)
`R_(eff)=R_1+R_2+R_3\\\\R_(eff)=21+58+64\\\\R_(eff)=143\Omega`

Equivalent resistance is 143 Ω

b) We know

Potential difference = Current x Resistance

V = IR

I = 0.5 A

R = 143Ω

Substituting

V = 0.5 x 143 = 71.5 V

Potential difference is 71.5 V