Question

A stunt pilot weighing 0.70 kN performs a vertical circular dive of radius 0.80 km.At the bottom of the dive, the pilot has a speed of 0.20 km/s which at that instant is notchanging. What force does the plane exert on the pilot?

Answer 1

Force plane exert on pilot = 4270 N

Step-by-step explanation:

first convert radius and speed to ms

using formula from force we know that

mass = weight/ gravity = 700 N/ 9.8N/kg= 71.4 kg

Fc= N-mg

N= Fc+ mg As Fc = mv²/R

N= mv²/R + mg

taking m common

N= m( v²/R +g)

= 71.4( (200)²/ 800 + 9.8 )

Force = 4270 N