Question

An air-track glider attached to a spring oscillates between the 12.0 cm mark and the 54.0 cm mark on the track. The glider completes 13.0 oscillations in 39.0 s .What is the angular frequency of the oscillations?

Answer 1

ω= 2.095rad/sec

Step-by-step explanation:

angular frequency(ω)=2πf

F is the frequency

Frequency of an oscillation is the number of cycles completed per second. One oscillation represents 1cycle. Thus for 13 oscillations, the glider completes 13 cycles.

F= 13/39 =
`(1)/(3)`Hz

angular frequency(ω)=2πf

angular frequency(ω)=2π *
`(1)/(3)`

= 2*
`(22)/(7)`*
`(1)/(3)`rad/sec

ω= 2.095rad/sec