Question

Factor completely.

y^2 - 12y + 32

A.
(y + 4)(y + 8)
B.
(y - 4)(y - 8)
C.
(y + 18)(y + 2)
D.
(y - 18)(y - 2)

Answer 1

Y^2-12y+32
Y^2-(8+4)y+32
Y^2-8y-4y+32
Y(y-8)-4(y-8)
(Y-8)(y-4)


It belongs to option C

Answer 2

B

Explanation:

Given

y² - 12y + 32

Consider the factors of the constant term (+ 32) which sum to give the coefficient of the y- term (- 12)

The factors are - 4 and - 8, since

- 4 × - 8 = 32 and - 4 - 8 = - 12, thus

y² - 12y + 32 = (y - 4)(y - 8) → B