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A 0.155 kg arrow is shot upward

at 31.4 m/s. What is its kinetic
energy (KE) when it is 30.0 m
above the ground?
KE (J)​

User IanS
by
5.5k points

2 Answers

4 votes

Answer: 244.05 J

Step-by-step explanation:

To find speed at 30 m above the ground use equation:

V²=Vo²-2Gs

V0=31.4m/s

s=30m

G=9.81m/s²

-----------------------

V²=31.4²-2*9.81*30

V²=985.96+588.6

V²=1574.56

V=39.68m/s ---speed of arrow on 30 m obove the ground

Use equation for kinetic enrgy:

Ke=mV²/2

m=0.155kg

V=39.68m/s

-------------------------

Ke=0.155kg*(39.68m/s)²/2

Ke=0.155*1574.5/2

Ke=244.05J

5 votes

Answer:

The answer is 30.8 (J)

Step-by-step explanation:

You're welcome

User Plamenko
by
6.4k points