Question

How many grams of MgCl, will be produced from 16.0 g of Mg(OH), and 11.0 g of HCl?

Answer 1

a) from Mg(OH)2:

m MgCL2 = 26.121 g

b) from HCl:

m MgCl2 = 14.362 g

Step-by-step explanation:

• Mg(OH)2 + 2HCl → MgCL2 + 2H2O

1 - Mg - 1

2 - Cl - 2

2 - O - 2

4 - H - 4

∴ Mw Mg(OH)2 = 58.3197 g/mol

∴ Mw HCl = 36.46 g/mol

∴ Mw MgCl2 = 95.211 g/mol

from Mg(OH)2:

⇒ m MgCL2 = (16.0 g Mg(OH)2)(mol Mg(OH)2/58.3197g)(mol MgCL2/mol Mg(OH)2)(95.211 g MgCl2/mol MgCl2) = 26.121 g MgCl2

from HCl:

⇒ m MgCL2 = (11 g HCl)(mol HCl/36.46g)(mol MgCl2/2 mol HCl)(95.211 gMgCl2/mol MgCl2) = 14.362 g MgCl2