Question

Which equation has the same solutions as the equation given below?

x^2 +18x+32=0

A. (x+4)^2=81

B. (x+9)^2=49

C. (x+6)^2=36

D. (x+2)^2=16

Answer 1

B.
`\displaystyle (x + 9)^2 = 49`

Step-by-step explanation:

For Quadratic Equations,
`\displaystyle y = Ax^2 + Bx + C,` use the formula
`\displaystyle [(b)/(2)]^2` to complete the square:

`\displaystyle (x^2 + 18x + 81) + k \\ (x^2 + 18x + 81) - 49 \\ \\ (x + 9)^2 - 49 → (x + 9)^2 = 49`

I am joyous to assist you anytime.

Answer 2

B

Explanation:

Also solved eveything

(x+9)^2=49

x^2+18x+81=49

x^2+18x+32=0

a=1, b=18 and c=32

x= (-18 +/- Sqrt (18^2-4×32))/2

x= (-18 +/- Sqrt (324-128))/2

x= (-18 +/- Sqrt (196))/2

x= (-18 +/- 14)/2

x= (-18 +14)/2 = -4/2 =-2

OR

x= (-18 -14)/2 = -32/2 =-16