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In the figure, if AB || CD, then angle EFD is equal to:

(a) 50
(d) 40
(c) 20
(d) 30​

In the figure, if AB || CD, then angle EFD is equal to: (a) 50 (d) 40 (c) 20 (d) 30​-example-1
User Munkay
by
5.5k points

2 Answers

3 votes

Answer:

d. 40°

Explanation:

70-30=40°

User Tomas Kubes
by
6.3k points
3 votes

Answer:

d) 40

Explanation:

AB || CD, so ∠DCB + ∠ABC = 180 { co interior angles }

∠DCB + 70 = 180

∠DCB = 180 -70 = 110

∠FCE = ∠DCB { Vertically opposite angles }

∠FCE = 110

In triangle CFE

∠EFD + ∠CEF + ∠FCE = 180 ( sum of angles of triangle)

∠EFD + 30 + 110 = 180

∠EFD + 140 = 180

∠EFD = 180 -140

∠EFD = 40

User Scott Ahten
by
6.0k points