Answer: x = 28/33, y = 25/23
( 28/23, 25/23)
Explanation:
3x + 4y = 8 ----------------------(1)
-2x + 5y = 3 ---------------------(2)
Using elimination method
Consider the coefficient of y in equation 1 and 2
Therefore multiply as follows
(1) x 5 -------- 15x + 20y = 40.
(2) x 4 -------- -8x + 20y = 12
Therefore carry out subtraction on the two equations
23x + 0y = 28
23x = 28
x = 28/23.
Now substitute for x in any of the equations above to get y
3(28/23) +4y = 8
84/23 +4y = 8
Multiply through by 23 to have s simple linear equation
84 + 92y = 184
Collect like terms
92y = 184 - 84
92y = 100
y = 100/92
Reduce to lowest term by dividing by 4
y = 25/33.
(28/23, 25/23)------ solution
Check
Substitute for x and y values in any equations above.
3(28/23) + 4(25/23)
84/23 + 100/23
Resolved into fraction with 23 as the common LCM
184/23
= 8